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2x^2-21x-125=0
a = 2; b = -21; c = -125;
Δ = b2-4ac
Δ = -212-4·2·(-125)
Δ = 1441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{1441}}{2*2}=\frac{21-\sqrt{1441}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{1441}}{2*2}=\frac{21+\sqrt{1441}}{4} $
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